(x+3)(x+1)=x^2+5

Solution for (x+3)(x+1)=x^2+5 equation:

Simplifying
(x + 3)(x + 1) = x2 + 5

Reorder the terms:
(3 + x)(x + 1) = x2 + 5

Reorder the terms:
(3 + x)(1 + x) = x2 + 5

Multiply (3 + x) * (1 + x)
(3(1 + x) + x(1 + x)) = x2 + 5
((1 * 3 + x * 3) + x(1 + x)) = x2 + 5
((3 + 3x) + x(1 + x)) = x2 + 5
(3 + 3x + (1 * x + x * x)) = x2 + 5
(3 + 3x + (1x + x2)) = x2 + 5

Combine like terms: 3x + 1x = 4x
(3 + 4x + x2) = x2 + 5

Reorder the terms:
3 + 4x + x2 = 5 + x2

Add '-1x2' to each side of the equation.
3 + 4x + x2 + -1x2 = 5 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
3 + 4x + 0 = 5 + x2 + -1x2
3 + 4x = 5 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
3 + 4x = 5 + 0
3 + 4x = 5

Solving
3 + 4x = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 4x = 5 + -3

Combine like terms: 3 + -3 = 0
0 + 4x = 5 + -3
4x = 5 + -3

Combine like terms: 5 + -3 = 2
4x = 2

Divide each side by '4'.
x = 0.5

Simplifying
x = 0.5